Multiply:

Question:

Multiply: 

(i) $\frac{-5}{17}$ by $\frac{51}{-60}$

(ii) $\frac{-6}{11}$ by $\frac{-55}{36}$

(iii) $\frac{-8}{25}$ by $\frac{-5}{16}$

(iv) $\frac{6}{7}$ by $\frac{-49}{36}$

(v) $\frac{8}{-9}$ by $\frac{-7}{-16}$

(vi) $\frac{-8}{9}$ by $\frac{3}{64}$

 

 

Solution:

(i) $\frac{-5}{17} \times \frac{51}{-60}=\frac{-5}{17} \times \frac{3 \times 17}{-5 \times 3 \times 4}=\frac{-5 \times 3 \times 17}{-17 \times 5 \times 3 \times 4}=\frac{1}{4}$

(ii)  $\frac{-6}{11} \times \frac{-55}{36}=\frac{-6}{11} \times \frac{-5 \times 11}{6 \times 6}=\frac{5}{6}$

(iii) $\frac{-8}{25} \times \frac{-5}{16}=\frac{-1}{5 \times 5} \times \frac{-5}{2}=\frac{1}{10}$

(iv) $\frac{6}{7} \times \frac{-49}{36}=\frac{6}{7} \times \frac{-7 \times 7}{6 \times 6}=\frac{-7}{6}$

(v) $\frac{8}{-9} \times \frac{-7}{-16}=\frac{1}{-9} \times \frac{-7}{-2}=\frac{-7}{18}$

(vi) $\frac{-8}{9} \times \frac{3}{64}=\frac{-8}{3 \times 3} \times \frac{3}{8 \times 8}=\frac{-1}{24}$

Leave a comment