Product of

Question:

Product of 6a2 – 7b + 5ab and 2ab is

(a) 12a3b – 14ab2 + 10ab

(b) 12a3b – 14ab2 + 10a2b2

(c) 6a2 – 7b + 7ab

(d) 12a2b – 7ab2 + 10ab

Solution:

(b) 12a3b – 14ab2 + 10a2b2

Now we have find product of trinomial and monomial,

= (6a2 – 7b + 5ab) × 2ab

= (2ab × 6a2) – (2ab × 7b) + (2ab × 5ab)

= 12a3b – 14ab2 + 10a2b2

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