Product of the following monomials

Question:

Product of the following monomials 4p, – 7q3, –7pq is

(a) 196 p2q4 

(b) 196 pq4 

(c) – 196 p2q4 

(d) 196 p2q3

Solution:

(a) 196 p2q4

= 4p × (– 7q3) × (–7pq)

= (4 × (-7) × (-7)) × p × q3 × pq

= 196p2q4

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