Question:
$\int \sec x(\sec x+\tan x) d x$
Solution:
$\int \sec x(\sec x+\tan x) d x$
$=\int\left(\sec ^{2} x+\sec x \tan x\right) d x$
$=\int \sec ^{2} x d x+\int \sec x \tan x d x$
$=\tan x+\sec x+\mathrm{C}$
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