Question: $\frac{1}{x}-\frac{1}{y}+\frac{1}{z}=4 ; \frac{2}{x}+\frac{1}{y}-\frac{3}{z}=0$
$\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=2 .(\mathrm{x}, \mathrm{y}, \mathrm{z} \neq 0)$
Solution:
To find: $-x, y, z$
Given set of lines are : -
$\therefore x=\frac{1}{2}, y=1, z=1$
