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Prove that

Question:

$\frac{1}{x}-\frac{1}{y}+\frac{1}{z}=4 ; \frac{2}{x}+\frac{1}{y}-\frac{3}{z}=0$

$\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=2 .(\mathrm{x}, \mathrm{y}, \mathrm{z} \neq 0)$

Solution:

To find: $-x, y, z$

Given set of lines are : -

$\therefore x=\frac{1}{2}, y=1, z=1$

 

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