Prove that

Question:

Prove that

$\cos 15^{\circ}-\sin 15=\frac{1}{\sqrt{2}}$

 

Solution:

L.H.S

$\Rightarrow \cos 15^{\circ}-\sin 15^{\circ}$

$\Rightarrow \cos \left(45^{\circ}-30^{\circ}\right)-\sin \left(45^{\circ}-30^{\circ}\right)$

$\Rightarrow\left(\cos 45^{\circ} \cos 30^{\circ}+\sin 45^{\circ} \sin 30^{\circ}\right)-\left(\sin 45^{\circ} \cos 30^{\circ}-\cos 45^{\circ} \sin 30^{\circ}\right)$

$\Rightarrow\left(\frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2}+\frac{1}{\sqrt{2}} \times \frac{1}{2}\right)-\left(\frac{1}{\sqrt{2}} \times \frac{\sqrt{3}}{2}-\frac{1}{\sqrt{2}} \times \frac{1}{2}\right)$

$\Rightarrow \frac{\sqrt{3}}{2 \sqrt{2}}+\frac{1}{2 \sqrt{2}}-\frac{\sqrt{3}}{2 \sqrt{2}}+\frac{1}{2 \sqrt{2}}$

$\Rightarrow \frac{2}{2 \sqrt{2}}$

$\Rightarrow \frac{1}{\sqrt{2}}$

 

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now