prove that

Question:

$\frac{8}{x}=\frac{5}{x-1}$

Solution:

Given, $\frac{8}{x}=\frac{5}{x-1}$'

$\Rightarrow$ $8(x-1)=5 x$ [by cross-multiplication]

$\Rightarrow \quad 8 x-8=5 x$

$\Rightarrow$  $8 x-5 x=8$  [transposing $5 x$ to LHS and $-8$ to RHS]

$\Rightarrow \quad 3 x=8$

$\Rightarrow$ $\frac{3 x}{3}=\frac{8}{3}$ [dividing both sides by 3 ]

$\therefore$ $x=\frac{8}{3}$

 

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