Prove the following

Question:

The value of (a + b)2 – (a – b)2 is

(a) 4ab

(b) – 4ab

(c) 2a2 + 2b2 

(d) 2a2 – 2b2

Solution:

(a) 4ab

The value of (a + b)2 – (a – b)2 = (a2 + b2 + 2ab) – (a2 + b2 – 2ab)

= a2 – a2 + b2 – b2 + 2ab + 2ab

= 4ab

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