Question:
Reaction of ammonia with excess $\mathrm{Cl}_{2}$ gives :
Correct Option: , 4
Solution:
$\mathrm{NH}_{3}+\underset{\text { excess }}{3 \mathrm{Cl}_{2}} \longrightarrow \mathrm{NCl}_{3}+3 \mathrm{HCl}$
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