Reaction of ammonia with excess

eSaral Updated on:
Question:

Reaction of ammonia with excess $\mathrm{Cl}_{2}$ gives :

 

  1. $\mathrm{NH}_{4} \mathrm{Cl}$ and $\mathrm{N}_{2}$

  2. $\mathrm{NCl}_{3}$ and $\mathrm{NH}_{4} \mathrm{Cl}$

  3. $\mathrm{NH}_{4} \mathrm{Cl}$ and $\mathrm{HCl}$

  4. $\mathrm{NCl}_{3}$ and $\mathrm{HCl}$

Correct Option: , 4

Solution:

$\mathrm{NH}_{3}+\underset{\text { excess }}{3 \mathrm{Cl}_{2}} \longrightarrow \mathrm{NCl}_{3}+3 \mathrm{HCl}$

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