Question:
Show that for a particle executing SHM, velocity, and displacement have a phase difference of π/2.
Solution:
The displacement equation of SHM, x = a cos ꞷt
Velocity, v = dx/dt = -aꞷ sin ꞷt
The phase displacement, ϕ1 = ꞷt
Phase velocity, ϕ2 = π/2 + ꞷt
Therefore, difference in phase of displacement = ϕ2 – ϕ1 = π/2
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