Solution of the differential equation $\cos x d y=y(\sin x-y) d x, 0
$\sec \mathrm{x}=(\tan \mathrm{x}+\mathrm{c}) \mathrm{y}$
$y \sec x=\tan x+c$
$y \tan x=\sec x+c$
$\tan x=(\sec x+c) y$
Correct Option: 1
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