Solve each of the following equation and also check your result in each case:

$\frac{7 y+2}{5}=\frac{6 y-5}{11}$

or $77 \mathrm{y}+22=30 \mathrm{y}-25$

or $77 \mathrm{y}-30 \mathrm{y}=-25-22$

or $47 \mathrm{y}=-47

or $\mathrm{y}=\frac{-47}{47}=-1$

Verification :

L. H. S. $=\frac{-7+2}{5}=\frac{-5}{5}=-1$

R. H. S. $=\frac{-6-5}{11}=\frac{-11}{11}=-1$

$\therefore$ L.H.S. $=$ R.H.S. for $y=-1$