Question:
Solve:
$\frac{15(2-y)-5(y+6)}{1-3 y}=10$
Solution:
$\frac{15(2-y)-5(y+6)}{1-3 y}=10$
$\Rightarrow \frac{30-15 y-5 y-30}{1-3 y}=10$
$\Rightarrow \frac{-20 y}{1-3 y}=10$
$\Rightarrow 1(-20 y)=10(1-3 y)$ (by cross multiplication)
$\Rightarrow-20 y=10-30 y$
$\Rightarrow-20 y+30 y=10$
$\Rightarrow 10 y=10$
$\Rightarrow y=\frac{10}{10}=1$
$\therefore y=1$
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