Solve the following

Question:

If $\frac{1}{x-2}<0$, then $x$ $2 .$

Solution:

If, $\frac{1}{x-2}<0$

$\Rightarrow x-2<0 \quad(\because+1>0)$

$\Rightarrow x<2 \quad$ (adding 2 on both sides)

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