Question: If $-\frac{3 x}{4} \leq-3$, then $x$ ______________ 4.
Solution:
Given $-\frac{3 x}{4} \leq-3$
i.e. $\quad-3 x \leq-12$
Now, multiplying both sides by $-\frac{1}{3}$,
We get,
$\left(-\frac{1}{3}\right)(-3 x) \geq\left(-\frac{1}{3}\right)(-12)$
i. e. $\quad x \geq 4$
