Solve the following

$\frac{5 x-6}{x+6}<1$

$\Rightarrow \frac{5 x-6}{x+6}-1<0$

$\Rightarrow \frac{5 x-6-x-6}{x+6}<0$

$\Rightarrow \frac{4 x-12}{x+6}<0$

$\Rightarrow \frac{x-3}{x+6}<0$

$\therefore x \in(-6,3)$