Question:
Solve:
$\frac{4 x+7}{9-3 x}=\frac{1}{4}$
Solution:
$\frac{4 x+7}{9-3 x}=\frac{1}{4}$
$\Rightarrow 4(4 x+7)=1(9-3 x) \quad$ (by cross multiplication)
$\Rightarrow 16 x+28=9-3 x$
$\Rightarrow 16 x+3 x=9-28$
$\Rightarrow 19 x=-19$
$\Rightarrow x=\frac{-19}{19}=-1$
$\therefore x=-1$
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