Question:
$\left(\frac{-3}{2}\right)^{-1}$ is equal to
(a) $\frac{2}{3}$
(b) $-\frac{2}{3}$
(c) $\frac{3}{2}$
(d) none of these
Solution:
(b) $-\frac{2}{3}$
We have:
$\left(\frac{-3}{2}\right)^{-1}=\frac{1}{(-3) / 2} \quad--->\left(a^{-1}=1 / a\right)$
$=\frac{2}{-3}$
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