If nC12 = nC8 , then n =
(a) 20
(b) 12
(c) 6
(d) 30
$n=12+8=20 \quad\left[\because{ }^{n} C_{x}={ }^{n} C_{y} \Rightarrow n=x+y\right.$ or $\left.x=y\right]$
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