Question:
Solve the following quadratic equations by factorization:
$6 x^{2}+11 x+3=0$
Solution:
We have been given
$6 x^{2}+11 x+3=0$
$6 x^{2}+9 x+2 x+3=0$
$3 x(2 x+3)+1(2 x+3)=0$
$(2 x+3)(3 x+1)=0$
$2 x+3=0$
$x=\frac{-3}{2}$
or,
$3 x+1=0$
$x=\frac{-1}{3}$
Hence $x=\frac{-3}{2}$ or $x=\frac{-1}{3}$.
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