Solve the inequality

$-12<4-\frac{3 x}{-5} \leq 2$

$\Rightarrow-12-4<\frac{-3 x}{-5} \leq 2-4$

$\Rightarrow-16<\frac{3 x}{5} \leq-2$

$\Rightarrow-80<3 x \leq-10$

Thus, the solution set for the given inequalityis $\left(\frac{-80}{3}, \frac{-10}{3}\right]$.

$\Rightarrow \frac{-80}{3}