Solve this

Question:

If $p(x)=x=4$, then $p(x)+p(-x)=?$

(a) 0

(b) 4

(c) $2 x$

(d) 8

 

Solution:

(d) 8

Let:

$p(x)=(x+4)$

$\therefore p(-x)=(-x)+4$

$=-x+4$

Thus, we have

$p(x)+p(-x)=\{(x+4)+(-x+4)\}$

= 4 + 4

=8

 

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