Solve this

Question:

$x^{2}+2=0$

 

Solution:

This equation is a quadratic equation

Solution of a general quadratic equation $a x^{2}+b x+c=0$ is given by:

$x=\frac{-b \pm \sqrt{\left(b^{2}-4 a c\right)}}{2 a}$

Given:

$\Rightarrow \mathrm{x}^{2}+2=0$

$\Rightarrow \mathrm{x}^{2}=-2$

$\Rightarrow \mathrm{x}=\pm \sqrt{(-2)}$

But we know that $\sqrt{(-1)}=\mathrm{i}$

$\Rightarrow x=\pm \sqrt{2} i$

Ans: $x=\pm \sqrt{2} i$

 

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