solve this

Question:

Let $(x+10)^{50}+(x-10)^{50}=a_{0}+a_{1} x+a_{2} x^{2}+\ldots \ldots$

$+\mathrm{a}_{50} \mathrm{x}^{50}$, for all $\mathrm{x} \in \mathrm{R}$, then $\frac{\mathrm{a}_{2}}{\mathrm{a}_{0}}$ is equal to:-

  1. $12.50$

  2. $12.00$

  3. $12.75$

  4. $12.25$


Correct Option: , 4

Solution:

$(10+x)^{50}+(10-x)^{50}$

$\Rightarrow a_{2}=2 .{ }^{50} C_{2} 10^{48}, a_{0}=2.10^{50}$

$\frac{\mathrm{a}_{2}}{\mathrm{a}_{0}}=\frac{{ }^{50} \mathrm{C}_{2}}{10^{2}}=12.25$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now