Solve this

Question:

Evaluate:

${ }^{6} \mathrm{P}_{6}$

 

Solution:

To find: the value of ${ }^{6} \mathrm{P}_{6}$

Formula Used:

Total number of ways in which $n$ objects can be arranged in $r$ places (Such that no object is replaced) is given by,

${ }_{n P_{r}}=\frac{n !}{(n-r) !}$

Therefore,

${ }_{6} \mathrm{P}_{6}=\frac{6 !}{(6-6) !}$

${ }^{62} P_{3}=6 \times 5 \times 4 \times 3 \times 2 \times 1=720$

Thus, the value of ${ }^{6} \mathrm{P}_{6}$ is 720 .

 

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