Question:
$\frac{2}{x}-\frac{3}{y}+\frac{3}{z}=10, \frac{1}{x}+\frac{1}{y}+\frac{1}{z}=10$
$\frac{3}{x}-\frac{1}{y}+\frac{2}{z}=13$
Ans. $x=\frac{1}{2}, y=\frac{1}{3}, z=\frac{1}{5}$
Solution:
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