Solve this following

Question:

If the angle between the lines, $\frac{x}{2}=\frac{y}{2}=\frac{z}{1}$ and $\frac{5-x}{-2}=\frac{7 y-14}{p}=\frac{z-3}{4}$ is $\cos ^{-1}\left(\frac{2}{3}\right)$, then $p$ is equal to:

  1. $-\frac{4}{7}$

  2. $\frac{7}{2}$

  3. $-\frac{7}{4}$

  4. $\frac{2}{7}$


Correct Option: , 2

Solution:

Solution not required

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