Question:
If $A=\left(\begin{array}{cc}2 x & 0 \\ x & x\end{array}\right)$ and $A^{-1}=\left(\begin{array}{cc}1 & 0 \\ -1 & 2\end{array}\right)$ then $x=?$
A. 1
B. 2
C. $\frac{1}{2}$
D. $-2$
Solution:
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