Someone is asked to take a number from 1 to 100.

Question:

Someone is asked to take a number from 1 to 100. The probability that it is a prime,is

(a) $\frac{1}{5}$

(b) $\frac{6}{25}$

(c) $\frac{1}{4}$

(d) $\frac{13}{50}$

 

Solution:

(c) Total numbers of outcomes $=100$

So, the prime numbers between 1 to 100 are $2,3,5,7,11,13,17,19,23,29,31,37,41.43,47,53,56,61,67,71$,

$73,79,83,89$ and 97 .

$\therefore$ Total number of possible outcomes $=25$

$\therefore$ Required probability $=\frac{25}{100}=\frac{1}{4}$

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