Question:
The additive inverse of $\frac{-7}{19}$ is
(a) $-7 / 19$
(b) $7 / 19$
(c) $19 / 7$
(d) $-19 / 7$
Solution:
Additive inverse of $(-7 / 19)$ is (b) $(7 / 19)$
The additive inverse of the rational number $-a / b$ is $a / b$ and vice-versa.
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