The common difference of the A.P. 1/2b,1−6b/2b,1−12b/2b, ... is

Question:

The common difference of the A.P. $\frac{1}{2 b}, \frac{1-6 b}{2 b}, \frac{1-12 b}{2 b}, \ldots$ is

(a) 2b
(b) −2b
(c) 3
(d) −3

Solution:

Let a be the first term and d be the common difference.

The given A.P. is $\frac{1}{2 b}, \frac{1-6 b}{2 b}, \frac{1-12 b}{2 b}, \ldots$

Common difference = d = Second term − First term

$=\frac{1-6 b}{2 b}-\frac{1}{2 b}$

$=\frac{-6 b}{2 b}=-3$

Hence, the correct option is (d).

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now