The common positive oxidation states for an element with atomic number 24, are :

Question:

The common positive oxidation states for an element with atomic number 24, are :

  1. $+2$ to $+6$

  2. $+1$ and $+3$ to $+6$

  3. $+1$ and $+3$

  4. $+1$ to $+6$


Correct Option: 1

Solution:

$\operatorname{Cr}(Z=24)$

$[\mathrm{Ar}] 4 \mathrm{~s}^{1} 3 \mathrm{~d}^{5} \mathrm{Cr}$ shows common oxidation states

starting from $+2$ to $+6$.

 

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