The coordination number of

Question:

The coordination number of $\mathrm{Th}$ in $\mathrm{K}_{4}\left[\mathrm{Th}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right]_{4}\left(\mathrm{OH}_{2}\right)_{2}\right]$ is :-

$\left(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}=\right.$ Oxalato $)$

  1. 6

  2. 10

  3. 14

  4. 8


Correct Option: , 2

Solution:

$\mathrm{C}_{2} \mathrm{O}_{4}^{2-}$ (oxalato): bidentate

$\mathrm{H}_{2} \mathrm{O}$ (aqua) : Monodentate

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