The curved surface area of a cylinder

Question:

The curved surface area of a cylinder is reduced by ____________ per cent if the height is half of the original height.

Solution:

50%

Explanation:

The CSA of cylinder with radius “r” and height “h” is 2πrh

When the height is halved, then new CSA is 2πr (h/2) = πrh

Hence, the percentage reduction in CSA = [(2πrh – πrh) (100)]/ 2πrh = 50%

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