The dipole moment of a circular loop carrying a current

Question:

The dipole moment of a circular loop carrying a current $\mathrm{I}$, is $\mathrm{m}$ and the magnetic field at the centre of the loop is $\mathrm{B}_{1}$. When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $B_{2}$. The ratio $\frac{B_{1}}{B_{2}}$ is :

 

  1. $\sqrt{3}$

  2. $\sqrt{2}$

  3. $\frac{1}{\sqrt{2}}$

  4. 2


Correct Option: , 2

Solution:

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