The distance of the point (1,0,2) from the point

Question:

The distance of the point $(1,0,2)$ from the point of intersection of the line

$\frac{x-2}{3}=\frac{y+1}{4}=\frac{z-2}{12}$ and the plane $x-y+z=16$, is :

  1. $3 \sqrt{21}$

  2. 13

  3. $2 \sqrt{14}$

  4. 8


Correct Option: , 2

Solution:

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