The logical statement $(\mathrm{p} \Rightarrow \mathrm{q})^{\wedge}(\mathrm{q} \Rightarrow \sim \mathrm{p})$ is equivalent to :
$\mathrm{p}$
$\mathrm{q}$
$\sim \mathrm{p}$
$\sim \mathrm{q}$
Correct Option: , 3
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