The mean and variance of 7 observations are 8 and 16 respectively.

Question:

The mean and variance of 7 observations are 8 and 16 respectively. If two observations are 6 and 8 , then the variance of the remaining 5 observations is:

  1. $\frac{92}{5}$

  2. $\frac{134}{5}$

  3. $\frac{536}{25}$

  4. $\frac{112}{5}$


Correct Option: , 3

Solution:

Let $8,16, x_{1}, x_{2}, x_{3}, x_{4}, x_{5}$ be the observations.

Now $\frac{x_{1}+x_{2}+\ldots+x_{5}+14}{7}=8$

$\Rightarrow \sum_{i=1}^{5} x_{i}=42$    ..........(1)

Also $\frac{x_{1}^{2}+x_{2}^{2}+\ldots x_{5}^{2}+8^{2}+6^{2}}{7}-64=16$

$\Rightarrow \sum_{i=1}^{5} x_{i}^{2}=560-100=460$     ..........(2)

So variance of $x_{1}, x_{2}, \ldots, x_{s}$

$=\frac{460}{5}-\left(\frac{42}{5}\right)^{2}=\frac{2300-1764}{25}=\frac{536}{25}$

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Comments

Ophelia Britt
Aug. 10, 2023, 6:35 a.m.
Hello esaral.com admin, Thanks for the well-organized and comprehensive post!
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