The mojor product of the following reaction is :

$\mathrm{CH}_{3} \mathrm{CD}(\mathrm{Cl}) \mathrm{CHD}$ (I)

$\mathrm{CH}_{3} \mathrm{CD}_{2} \mathrm{CH}(\mathrm{Cl})$ (I)

$\mathrm{CH}_{3} \mathrm{CD}(\mathrm{I}) \mathrm{CHD}(\mathrm{Cl})$

$\mathrm{CH}_{3} \mathrm{C}(\mathrm{I})(\mathrm{Cl}) \mathrm{CHD}_{2}$