Question:
The parallel sides of a trapezium are 12 cm and 9 cm and the distance between them is 8 cm. Find the area of the trapezium.
Solution:
Area of the trapezium $=\frac{1}{2} \times$ (sum of the parallel sides) $\times$ distance between the parallel sides
$=\frac{1}{2} \times(12+9) \times 8$
$=21 \times 4$
$=84 \mathrm{~cm}^{2}$
So, the area of the trapezium is 84 cm2.
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