The population of a town increases by 10% annually.

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Question:

The population of a town increases by 10% annually. If the present population is 60000, what will be itsĀ  population after 2 years?

Solution:

Present population $=60000$

It increases by $10 \%$ annually.

$\therefore$ Increase in the population in the first year $=10 \%$ of $60000=\frac{10}{100} \times 60000$

$=6000$

$\therefore$ Population after 1 year $=60000+6000=66000$

Increase in the population in the second year, $10 \%$ of $66000=\frac{10}{100} \times 66000$

$=6600$

Thus, population after 2 years $=66000+6600=72600$

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