Question:
The probability of a man hitting a target is 0.25. He shoots 7 times. What is the probability of his hitting at least twice?
Solution:
Here, we have n = 7, p = 0.25 = 25/100 = ¼ and q = 1 – ¼ = ¾
P(X ≥ 2) = 1 – [P(X = 0) + P(X = 1)]
Therefore, the required probability is 4547/8192.
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