The product of two rational numbers is

Question:

The product of two rational numbers is $\frac{-16}{9}$. If one of the numbers is $\frac{-4}{3}$, find the other.

Solution:

Let the number be $\mathrm{x}$.

Now,

$\mathrm{x} \times \frac{-4}{3}=\frac{-16}{9}$

$\Rightarrow \mathrm{x}=\frac{-16}{9} \div \frac{-4}{3}$

$\Rightarrow \mathrm{x}=\frac{-16}{9} \times \frac{3}{-4}$

$\Rightarrow \mathrm{x}=\frac{-16 \times 3}{9 \times(-4)}$

$\Rightarrow \mathrm{x}=\frac{48}{36}$

$\Rightarrow \mathrm{x}=\frac{4}{3}$

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