The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product

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Question:

The reaction of white phosphorus on boiling with alkali in inert atmosphere resulted in the formation of product 'A'. The reaction $1 \mathrm{~mol}$ of 'A' with excess of $\mathrm{AgNO}_{3}$ in aqueous medium gives $\mathrm{mol}(\mathrm{s})$ of $\mathrm{Ag}$. (Round off to the Nearest Integer).

Solution:

$\mathrm{P}_{4}+3 \mathrm{OH}^{-}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{PH}_{3}+\underset{(\mathrm{A})}{3 \mathrm{H}_{2} \mathrm{PO}_{2}^{-}}$

$\underset{1 \text { mole }}{\mathrm{H}_{2} \mathrm{PO}_{2}^{-}}+\underset{\text { excess }}{4 \mathrm{Ag}^{+}}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \underset{4 \text { mole }}{4 \mathrm{Ag}+\mathrm{H}_{3} \mathrm{PO}_{4}}+3 \mathrm{H}^{+}$

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