The sum of three consecutive numbers is 156.

Let three consecutive numbers be $x_{1}(x+1)$ and $(x+2)$. According to the question,

$x+(x+1)+(x+2)=156$ [given]

$\Rightarrow$ $3 x+3=156 \Rightarrow 3 x=156-3=153$

$\therefore$ $x=153 \times \frac{1}{3}=51$

Thus, we get the numbers $51,51+1$ and $51+2, i . e, 51,52$ and 53 . Out of these, only 52 is a multiple of $13 .$