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The symmetric difference of A

Question:
The symmetric difference of A = {1, 2, 3} and B = {3, 4, 5} is

(a) {1, 2}

(b) {1, 2, 4, 5}

(c) {4, 3}

(d) {2, 5, 1, 4, 3}

Solution:

(b) {1, 2, 4, 5}

Here,

A = {1, 2, 3} and B = {3, 4, 5}

The symmetric difference of A and B is given by :-

$(A-B) \cup(B-A)$

Now, we have:

$(A-B)=\{1,2\}$

$(B-A)=\{4,5\}$

$(A-B) \cup(B-A)=\{1,2,4,5\}$

None

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