Question:
The value of nPr + nCr is ___________.
Solution:
${ }^{n} P_{r} \div{ }^{n} C_{r}=\frac{{ }^{n} P_{r}}{{ }^{n} C_{r}}$
$=\frac{n !}{(n-r) !} \times \frac{(n-r) ! r !}{n !}$
Therefore, ${ }^{n} P_{r} \div{ }^{n} C_{r}=r$
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