The value of

Question:

The value of nPr + nCr is ___________.

Solution:

${ }^{n} P_{r} \div{ }^{n} C_{r}=\frac{{ }^{n} P_{r}}{{ }^{n} C_{r}}$

$=\frac{n !}{(n-r) !} \times \frac{(n-r) ! r !}{n !}$

Therefore, ${ }^{n} P_{r} \div{ }^{n} C_{r}=r$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now