The volume of the frustum of a cone is
Question:

The volume of the frustum of a cone is $\frac{1}{3} \pi h\left[r_{1}^{2}+r_{2}^{2}-r_{1} r_{2}\right]$, where $h$ is vertical height of the frustum and $r_{1}, r_{2}$ are the radii of the ends.

Solution:

False

Since, the volume of the frustum of a cone is $\frac{1}{3} \pi h\left[r_{1}^{2}+r_{2}^{2}+r_{1} r_{2}\right]$, where $h$ is vertical height of the frustum

and $r_{1}, r_{2}$ are the radii of the ends.