Question:
The zeroes of the polynomial $p(x)=x^{2}-3 x$ are
(a) 0,0
(b) 0,3
(c) $0,-3$
(d) $3,-3$
Solution:
(b) 0, 3
Let:
$p(x)=x^{2}-3 x$
Now, we have:
$p(x)=0 \Rightarrow x^{2}-3 x=0$
$\Rightarrow x(x-3)=0$
$\Rightarrow x=0$ and $x-3=0$
$\Rightarrow x=0$ and $x=3$
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