The zeros of the polynomial p(x)

Question:

The zeros of the polynomial $p(x)=x^{2}+x-6$ are

(a) 2,3

(b) $-2,3$

(c) $2,-3$

(d) $-2,-3$

 

Solution:

The given polynomial is $p(x)=x^{2}+x-6$.

Putting x = 2 in p(x), we get

$p(2)=2^{2}+2-6=4+2-6=0$

Therefore, x = 2 is a zero of the polynomial p(x).

Putting x = –3 in p(x), we get

$p(-3)=(-3)^{2}-3-6=9-9=0$

Therefore, x = –3 is a zero of the polynomial p(x).

Thus, 2 and –3 are the zeroes of the given polynomial p(x).

Hence, the correct answer is option (c).

 

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